Translated material
A ticket to the Champions League "Zenit" will play with the Belgian "Standard"
The St. Petersburg Zenit in the qualification round of the Champions League playoffs will play against the Belgian "Standard".
These are the results of the drawing of the decisive stage of the qualifying tournament of the most prestigious football European cup, held on Friday in the Swiss Nyon.
Matches will take place on 19/20 and August 26/27. The first meeting will be held in Liege, reports ufa.com .
The winner of a two -match confrontation will perform in the Champions League group tournament, and the loser in the European League group tournament.
Note that the St. Petersburg club had previously beaten the "Standard" in the first circle of the UEFA-2007/08 Cup on the way to the conquest of its only Eurotrofaus.
The results of the draw:
| "Maribor" (Slovakia) - "Celtic" (Scotland) |
| "Salzburg" (Austria) - "Malma" (Sweden) |
| "Alborg" (Denmark) - Apoel (Cyprus) |
| "Stayaa" (Romania) - "Ludogorets" (Bulgaria) |
| "Slovan" (Czech Republic) - "BATE" (Belarus) |
| "Besiktash" (Türkiye) - "Arsenal" (England) |
| "Standard" (Belgium) - "Zenit" (Russia) |
| "Copenhagen" (Denmark) - "Bayer 04" (Germany) |
| "Lill" (France) - "Porto" (Portugal) |
| "Napoli" (Italy) - "Athletic" Bilbao (Spain) |